20y(2y-1)=40y^2-20y

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Solution for 20y(2y-1)=40y^2-20y equation: 


Simplifying
20y(2y + -1) = 40y2 + -20y

Reorder the terms:
20y(-1 + 2y) = 40y2 + -20y
(-1 * 20y + 2y * 20y) = 40y2 + -20y
(-20y + 40y2) = 40y2 + -20y

Reorder the terms:
-20y + 40y2 = -20y + 40y2

Add '20y' to each side of the equation.
-20y + 20y + 40y2 = -20y + 20y + 40y2

Combine like terms: -20y + 20y = 0
0 + 40y2 = -20y + 20y + 40y2
40y2 = -20y + 20y + 40y2

Combine like terms: -20y + 20y = 0
40y2 = 0 + 40y2
40y2 = 40y2

Add '-40y2' to each side of the equation.
40y2 + -40y2 = 40y2 + -40y2

Combine like terms: 40y2 + -40y2 = 0
0 = 40y2 + -40y2

Combine like terms: 40y2 + -40y2 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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